Question on: WAEC Mathematics - 2010
In the diagram, < WOX = 60o, < YOE = 50o and < OXY = 30o. What is the bearing of x from y?
A
300o
B
240o
C
190o
D
150o
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Correct Option: A
The bearing of x from y = 270o + \(\theta\)
where \(\theta\) + 50o = y
in \(\bigtriangleup\) OXY
O + X + Y = 180o
Where O = 40o + 30o = 70o
70o + 30o + y = 180o
y + 100o = 180o
y = 180o - 100o = 30o
\(\theta\) + 50o = 80o
80o - 50o = 30o
The bearing of x from y = 270o + 30o = 300o
where \(\theta\) + 50o = y
in \(\bigtriangleup\) OXY
O + X + Y = 180o
Where O = 40o + 30o = 70o
70o + 30o + y = 180o
y + 100o = 180o
y = 180o - 100o = 30o
\(\theta\) + 50o = 80o
80o - 50o = 30o
The bearing of x from y = 270o + 30o = 300o
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