Question on: WAEC Mathematics - 1989
In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR.
A
14o
B
28o
C
31o
D
45o
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Correct Option: B
< QSR = 90° (angle in a semi-circle)
\(\therefore\) < SQR = 180° - (90° + 62°)
= 28°
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