Question on: JAMB Mathematics - 1993

In the diagram, O is the centre of the circle and POQ a diameter. If POR = 96o, find the value of ORQ.
A
84o
B
48o
C
45o
D
42o
Ask EduPadi AI for a detailed answer
Correct Option: B

OQ = OR = radii

< ROQ = 180 - 86 = 84o

(\bigtriangleup)OQR = Isosceles

R = Q

R + Q + 84 = 180(angle in a (\bigtriangleup))

2R = 96 since R = Q

R = 48o

ORQ = 48o

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