In the diagram PO and OR are radii PQ QR and re... - WAEC Mathematics 2011 Question

< Q = \(\frac{240}{2}\) (angle at centre twice that at the circumference)

< Q = 120^o

Also < POR = 360 - 240

= 120^o

( < s at centre) since /PQ/ = /QR/, < x = < R

Byt < x + < R + O + Q = 360 (sum of interior < s of quadrilateral)

x + R + 120 = 360^o

x + R = 360 - 240 = 120; Since x = R

x + x = 120

2x = 120

Since x = R

x + x = 120

2x = 120

x = \(\frac{120}{2}\)

= 60^o