In the diagram PR SV WY TX QY lt PQT 48o and lt... - WAEC Mathematics 2016 Question

In the diagram, < TUQ + 60^o(corresp. angles)

< QTU = 48^o (alternate angles)

< QU + 60^o + 48^o = 180^o(sum of angles of a \(\Delta\))

< TQU = 180^o - 108^o

= 72^o