Question on: WAEC Mathematics - 2016
In the diagram, PR||SV||WY|, TX||QY|, < PQT = 48o and < TXW = 60o.Find < TQU.
A
120o
B
108o
C
72o
D
60o
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Correct Option: C
In the diagram, < TUQ + 60o(corresp. angles)
< QTU = 48o (alternate angles)
< QU + 60o + 48o = 180o(sum of angles of a \(\Delta\))
< TQU = 180o - 108o
= 72o
< QTU = 48o (alternate angles)
< QU + 60o + 48o = 180o(sum of angles of a \(\Delta\))
< TQU = 180o - 108o
= 72o
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