In the diagram PST is a straight line PQ QS RS ... - JAMB Mathematics 2002 Question
In the diagram, PST is a straight line, PQ = QS = RS. If < RST = 72o, find x
A
24o
B
72o
C
18o
D
36o
correct option: d
< QPS = < QSP = QRS = X
since PQ = QS = RS
< RQS = 2x - exterior angle
< RSQ = 180 - x
2x + x(188 - x) = 180
3x + 108 - x = 180 - x
2x + 108 = 180
2x = 180 - 108 = 72
x = \(\frac{72}{2}\)
= 36o
since PQ = QS = RS
< RQS = 2x - exterior angle
< RSQ = 180 - x
2x + x(188 - x) = 180
3x + 108 - x = 180 - x
2x + 108 = 180
2x = 180 - 108 = 72
x = \(\frac{72}{2}\)
= 36o
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