In the diagram PX is a tangent to the circle an... - WAEC Mathematics 2008 Question
In the diagram, PX is a tangent to the circle and RST is an equilateral triangle. Calculate < PTS
A
60o
B
90o
C
120o
D
150o
correct option: c
\(\bigtriangleup\) RST is equilateral triangle, hence
< TRS = < RTS = < RSt = 60o
But < PTR = 60o(Angle between a chord and a tangent at the point of contact = Angle in the alt. segment). From the diagram < PTS = < PTR + < RTS
= 60o + 60o = 120o
< TRS = < RTS = < RSt = 60o
But < PTR = 60o(Angle between a chord and a tangent at the point of contact = Angle in the alt. segment). From the diagram < PTS = < PTR + < RTS
= 60o + 60o = 120o
Please share this, thanks:
Add your answer
No responses