In the diagram QPS SPR PR 9cm PQ 4cm and QS 3cm... - JAMB Mathematics 1993 Question
A
6\(\frac{3}{4}\)cm
B
3\(\frac{3}{8}\)cm
C
4\(\frac{3}{8}\)cm
D
2\(\frac{3}{8}\)cm
correct option: a
Using angle bisector theorem: line PS bisects angle QPR
QS/QP = SR/PR
3/4 = SR/g
4SR = 27
SR = \(\frac{27}{4}\)
= 6\(\frac{3}{4}\)cm
QS/QP = SR/PR
3/4 = SR/g
4SR = 27
SR = \(\frac{27}{4}\)
= 6\(\frac{3}{4}\)cm
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