Question on: JAMB Mathematics - 1993
A
6\(\frac{3}{4}\)cm
B
3\(\frac{3}{8}\)cm
C
4\(\frac{3}{8}\)cm
D
2\(\frac{3}{8}\)cm
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Correct Option: A
Using angle bisector theorem: line PS bisects angle QPR
QS/QP = SR/PR
3/4 = SR/g
4SR = 27
SR = (\frac{27}{4})
= 6(\frac{3}{4})cm
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