In the diagram QP ST PQR 34o qrs 73o and Rs RT ... - JAMB Mathematics 1993 Question

In the diagram, QP//ST:PQR = 34^o qrs = 73^o and Rs = RT. Find SRT

Construction joins R to P such that SRP = straight line

R = 180^o - 107^o

< p = 180^o - (107^o - 34^o)

108 - 141^o = 39^o

Angle < S = 39^o (corr. Ang.) But in (\bigtriangleup)SRT

< S = < T = 39^o

SRT = 180 - (39^o + 39^o)

= 180^o - 78^o

= 102^o