In the diagram QR 10m SR 8m lt QPS 30o lt QRP 9... - WAEC Mathematics 2012 Question
In the diagram, |QR| = 10m, |SR| = 8m
< QPS = 30o, < QRP = 90o and |PS| = x, Find x
< QPS = 30o, < QRP = 90o and |PS| = x, Find x
A
1.32m
B
6.32m
C
9.32m
D
17.32
correct option: c
In right angled (\bigtriangleup)QPR
tan 30o = (\frac{10}{x + 8})
(x + 8) tan 30 = 10
x + 8 = (\frac{10}{0.5773})
x +8 = 17.3
x = 17.3 - 8
x = 9.32
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