Question on: WAEC Mathematics - 2006
In the diagram, |QR| = 5cm, PQR = 60o and PSR = 45o. Find |PS|, leaving your answe in surd form.
A
4\(\sqrt{5}\)cm
B
3\(\sqrt{7}\)cm
C
4\(\sqrt{6}\)cm
D
5\(\sqrt{6}\)cm
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Correct Option: D
tan 6o = (\frac{|PR|}{|QR|})
(\sqrt{3} = \frac{|PR|}{5})
= |PR| = (5 \sqrt{3})cm
sin 45 = (\frac{|PR|}{|PS|})
(\frac{1}{\sqrt{2}}) = (\frac{5 \sqrt{3}}{|PS|})
|PS| = (5 \sqrt{3}) x (\sqrt{2})
= 5(\sqrt{6})cm
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