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In the diagram QTR is a straight line and lt PQ... - JAMB Mathematics 1998 Question

In the diagram, QTR is a straight line and < PQT = 30o. find the sin of < PTR
A
\(\frac{8}{15}\)
B
\(\frac{2}{3}\)
C
\(\frac{3}{4}\)
D
\(\frac{15}{16}\)
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Correct Option: C

(\frac{10}{\sin 30^o} = \frac{15}{\sin x} = \frac{10}{0.5} = \frac{15}{\sin x})

(\frac{15}{20} = \sin x)

sin x = (\frac{15}{20} = \frac{3}{4})

N.B x = < PRQ

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