Question on: JAMB Mathematics - 1999

In the figure above, PQRS is a circle with ST//RQ. Find the value of x PT = PS.
A
70o
B
55o
C
40o
D
35o
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Correct Option: B

PQRS is a cyclic quad
^P = 180 - 110 (opp ∠s of a cyclic quad)
^P = 70

In ΔPTS, ^S = ^T (base ∠s of Isc Δ)

^T = (180-70) / 2

= 110/2

= 55o

But ^T x(corr ∠)

∴x =55

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