In the figure PQRS is a circle with ST RQ Find ... - JAMB Mathematics 1999 Question

A
70o
B
55o
C
40o
D
35o
correct option: b
< PST = < RQT = x(corresponding angle)
< PST = < PTS = < PTS x (PS = PT0
< SRQ = < SPT = 180o (sum of < on straight line)
< SPT = 180o - 110o = 70o
in < SPT, < PST = PTS = < PSt = 180o
2x + 70 = 180o
2x = 180o - 70o = 110o
x = (\frac{110^o}{2}) = 55o
Please share this, thanks:
#JAMB #JAMB
Add your answer
No responses