Question on: JAMB Mathematics - 1998

In the figure, PQST is a parallelogram and TSR is a straight line. If the area of \(\bigtriangleup\)QRS is 20cm2, find the area of the trapezium PQRT.
A
35cm2
B
65cm2
C
70cm2
D
140cm2
Ask EduPadi AI for a detailed answer
Correct Option: C
A\(\bigtriangleup\) = \(\frac{1}{2}\) x 8 x h = 20

= \(\frac{1}{2}\) x 8 x h = 4h

h = \(\frac{20}{4}\)

= 5cm

A\(\bigtriangleup\)(PQTS) = L x H

A\(\bigtriangleup\)PQRT = A\(\bigtriangleup\)QSR + A\(\bigtriangleup\)PQTS

20 + 50 = 70cm2

ALTERNATIVE METHOD

A\(\bigtriangleup\)PQRT = \(\frac{1}{2}\) x 5 x 28

= 70cm2

Add your answer

Notice: Please post responsibly.

Please share this, thanks!

No responses