In the figure PQST is a parallelogram and TSR i... - JAMB Mathematics 1998 Question

A_{\(\bigtriangleup\)} = \(\frac{1}{2}\) x 8 x h = 20

= \(\frac{1}{2}\) x 8 x h = 4h

h = \(\frac{20}{4}\)

= 5cm

A_{\(\bigtriangleup\)}(PQTS) = L x H

A_{\(\bigtriangleup\)PQRT} = A_{\(\bigtriangleup\)QSR} + A_{\(\bigtriangleup\)PQTS}

20 + 50 = 70cm²

ALTERNATIVE METHOD

A_{\(\bigtriangleup\)PQRT} = \(\frac{1}{2}\) x 5 x 28

= 70cm²