In the figure YXZ 30o XYZ 105o and XY 8cm Calcu... - JAMB Mathematics 1990 Question

yzx + 105^o + 30^o = 180^o

yzx = 180 - 155 = 45^o

(\frac{yz}{sin 30^o} = \frac{8}{sin 45^o})

yz = (\frac{8 \sin 30}{sin 45})

= 8((\frac{1}{2}) = \frac{8}{1} \times \frac{1}{2} \times \frac{\sqrt{2}}{1})

= 4 (\div) (\frac{1}{\sqrt{2}})

= 4(\sqrt{2})cm