In the parallelogram PQRS given find anle SQR - JAMB Mathematics 2006 Question

A
50o
B
80o
C
80cm2
D
100o
correct option: d
< QRS = 30o(corresponding < ), < QSR = 50o
< SQR = 180o - (30 + 50)o (Sum of < S in a (\bigtriangleup))
180o - 80o = 100o
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