Question on: SS2 Mathematics - Probability

In the toss of a coin thrice, find the probability of three tails appearing.

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A
\(\frac{3}{2}\)
B
\(\frac{2}{3}\)
C
\(\frac{1}{8}\)
D
\(\frac{3}{4}\)
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Correct Option: C

\(probability\ of\ 3\ tails,\ P(TTT) = P(tail\ in\ 1st\ toss) + P(tail\ in\ 2nd\ toss) + P(tail\ in\ 3rd\ toss)\) (independent events)

\(P(TTT) = P(A \cap B \cap C) = P(A)P(B)P(C) = (\frac{1}{2})(\frac{1}{2})(\frac{1}{2}) = \frac{1}{8}\)

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