In this figure PQ PR PS and SRT 68o Find QPS - JAMB Mathematics 1991 Question

Since PQRS is quadrilateral 2y + 2x = QPS = 360^o

i.e. 2(y + x) + QPS = 360^o

QPS = 360^o - 2(y + x)

But x + y + 68^o = 180^o

x + y = 180^o - 68^o = 180^o

x + y = 180^o - 68^o

= 112^o

QPS = 360^o - 2(112^o)

360^o - 224^o = 136^o