Question on: JAMB Mathematics - 1991

In this figure, PQ = PR = PS and SRT = 68^o. Find QPS

136^o

124^o

12^o

68^o

Ask EduPadi AI for a detailed answer

Correct Option: A

Since PQRS is quadrilateral 2y + 2x = QPS = 360^o

i.e. 2(y + x) + QPS = 360^o

QPS = 360^o - 2(y + x)

But x + y + 68^o = 180^o

x + y = 180^o - 68^o = 180^o

x + y = 180^o - 68^o

= 112^o

QPS = 360^o - 2(112^o)

360^o - 224^o = 136^o

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