In this fiqure PQ PR PS and SRT 68 o Find QPS - JAMB Mathematics 2020 Question
In this fiqure, PQ = PR = PS and SRT = 68\(^o\). Find QPS
A
136\(^o\)
B
124\(^o\)
C
112\(^o\)
D
68\(^o\)
correct option: a
PQRS is quadrilateral. Hence,
2y + 2x + QPS = 360\(^o\)
i.e. (y + x) + QPS = 360\(^o\)
QPS = 360\(^o\) - 2 (y + x)
But x + y + 68\(^o\) = 180\(^o\)
Therefor,
x + y = 180\(^o\) - 68\(^o\) = 112\(^o\)
QPS = 360 - 2(112\(^o\))
= 360\(^o\) - 224
= 136\(^o\)
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