Question on: JAMB Mathematics - 2008
\(\int ^{\frac{\pi}{2}}_{-\frac{\pi}{2}}\)cosx dx
A
7
B
1
C
2
D
3
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Correct Option: B
\(\int ^{\frac{\pi}{2}}_{-\frac{\pi}{2}}\)cosx
\([sin x]^{\frac{\pi}{2}}_{\frac{\pi}{2}}\)
= sin\(\frac{\pi}{2}\)- (-sin \(\frac{\pi}{2}\))
= sin \(\frac{\pi}{2}\) + sin \(\frac{\pi}{2}\)
= 2 sin \(\frac{\pi}{2}\)
= 2 sin 1.5714
= 2(0.2704)
= 0.5
= 1
\([sin x]^{\frac{\pi}{2}}_{\frac{\pi}{2}}\)
= sin\(\frac{\pi}{2}\)- (-sin \(\frac{\pi}{2}\))
= sin \(\frac{\pi}{2}\) + sin \(\frac{\pi}{2}\)
= 2 sin \(\frac{\pi}{2}\)
= 2 sin 1.5714
= 2(0.2704)
= 0.5
= 1
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