Question on: SS3 Mathematics - Matrices and Determinants
Let \(A = \begin{bmatrix} 2 & - 4 & 3 \\ 5 & 1 & 0 \\ \end{bmatrix}\) and \(B = \begin{bmatrix} 1 & 4 & - 2 \\ - 3 & 3 & - 1 \\ \end{bmatrix}\). Find \(B - A\)
\[\begin{bmatrix} - 1 & 8 & - 5 \\ - 8 & 2 & - 1 \\ \end{bmatrix}\]
\[\begin{bmatrix} - 1 & 4 & 5 \\ 8 & 2 & - 1 \\ \end{bmatrix}\]
\[\begin{bmatrix} 1 & 8 & 5 \\ 8 & 2 & 1 \\ \end{bmatrix}\]
\[\begin{bmatrix} 2 & 4 & 1 \\ 0 & 6 & 3 \\ \end{bmatrix}\]
Let \(A = \begin{bmatrix} 2 & - 4 & 3 \\ 5 & 1 & 0 \\ \end{bmatrix}\) and \(B = \begin{bmatrix} 1 & 4 & - 2 \\ - 3 & 3 & - 1 \\ \end{bmatrix}\)
\[B - A = \begin{bmatrix} 1 - 2 & 4 - ( - 4) & - 2 - 3 \\ - 3 - 5 & 3 - 1 & - 1 - 0 \\ \end{bmatrix}\]
\(= \begin{bmatrix} - 1 & 8 & - 5 \\ - 8 & 2 & - 1 \\ \end{bmatrix}\)
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