Question on: WAEC Physics - 2005
Light of energy 5.0 eV falls on a metal of work function 3.0 eV and electrons are emitted, determine the stopping potential. [electronic charge, e = 1.60 x 108ms-19]
A
1.7V
B
2.0V
C
8.0V
D
15.0V
Ask EduPadi AI for a detailed answer
Correct Option: B
(V_8 \frac{hf - w_o}{e} = \frac{5.0 \times 1.60 \times 10^{-19} - 3.0 \times 1.6 \times 10^{-19}}{1.6 \times 10^{-19}} = 2.0V)
Add your answer
Please share this, thanks!
No responses