Question on: JAMB Mathematics - 1998
Make \(\frac{a}{x}\) the subject of formula \(\frac{x + 1}{x - a}\)
A
\(\frac{m - 1}{m + 1}\)
B
\(\frac{m + 1}{1 - m}\)
C
\(\frac{m - 1}{1 + m}\)
D
\(\frac{m + 1}{m - 1}\)
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Correct Option: A
\(\frac{x + a}{x - a}\) = m
x + a = mx - ma
a + ma = mx - x
a(m + 1) = x(m - 1)
\(\frac{a}{x}\) = \(\frac{m - 1}{m + a}\)
x + a = mx - ma
a + ma = mx - x
a(m + 1) = x(m - 1)
\(\frac{a}{x}\) = \(\frac{m - 1}{m + a}\)
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