Make K the subject of the relation T sqrt frac ... - WAEC Mathematics 2015 Question
Make K the subject of the relation T = (\sqrt{\frac{TK - H}{K - H}})
A
K = \(\frac{H(T^2 - 1)}{T^2 - T}\)
B
K = \(\frac{HT}{(T - 1)^2}\)
C
K = \(\frac{H(T^2 + 1)}{T}\)
D
K = \(\frac{H(T - 1)}{T}\)
Ask EduPadi AI...
Correct Option: A
T = (\sqrt{\frac{TK - H}{K - H}})
Taking the square of both sides, give
T2 = (\frac{TK - H}{K - H})
T2(K - H) = TK - H
T2K - T2H = TK - H
T2K - TK = T2H - H
K(T2 - T) = H(T2 - 1)
K = (\frac{H(T^2 - 1)}{T^2 - T})
Please share this, thanks:
#WAEC #WAEC
Add your answer
No responses