Question on: WAEC Mathematics - 2012
Make p the subject of the relation: q = \(\frac{3p}{r} + \frac{s}{2}\)
A
p = \(\frac{2q - rs}{6}\)
B
p = 2qr - sr - 3
C
p = \(\frac{2qr - s}{6}\)
D
p = \(\frac{2qr - rs}{6}\)
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Correct Option: D
q = \(\frac{3p}{r} + \frac{s}{2}\)
q = \(\frac{6p + rs}{2r}\)
6p + rs = 2qr
6p = 2qr - rs
p = \(\frac{2qr - rs}{6}\)
q = \(\frac{6p + rs}{2r}\)
6p + rs = 2qr
6p = 2qr - rs
p = \(\frac{2qr - rs}{6}\)
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