Make p the subject of the relation q frac 3p r ... - WAEC Mathematics 2012 Question
Make p the subject of the relation: q = (\frac{3p}{r} + \frac{s}{2})
A
p = \(\frac{2q - rs}{6}\)
B
p = 2qr - sr - 3
C
p = \(\frac{2qr - s}{6}\)
D
p = \(\frac{2qr - rs}{6}\)
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Correct Option: D
q = (\frac{3p}{r} + \frac{s}{2})
q = (\frac{6p + rs}{2r})
6p + rs = 2qr
6p = 2qr - rs
p = (\frac{2qr - rs}{6})
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