Question on: WAEC Mathematics - 2007
make w the subject of the relation \(\frac{a + bc}{wd + f}\) = g
A
\(\frac{a + bc - fg}{dg}\)
B
\(\frac{a - bc + fg}{dg}\)
C
\(\frac{a + bc - f}{dg}\)
D
\(\frac{a + bc - dg}{dg}\)
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Correct Option: A
\(\frac{a + bc}{wd + f}\) = g(cross multiply)
a = bc + wdg + fg
wdg = a + bc - fg
w = \(\frac{a + bc - fg}{dg}\)
a = bc + wdg + fg
wdg = a + bc - fg
w = \(\frac{a + bc - fg}{dg}\)
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