Question on: JAMB Mathematics - 2015
Make x the subject of the equation
s = 2 + \(\frac{t}{5} \)(x + β y)
s = 2 + \(\frac{t}{5} \)(x + β y)
A
x = 5[(s β 2) Γ· t] + 3yt
B
x = 25[(s β 2) Γ· t] β 3ty
C
x = [1 Γ· (s β 2)3ty]
D
x = [5(s β 2) 2 Γ· 3ty] Γ t
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Correct Option: B
2 + t/5(x + 3/5y ) = s
t/5(x + 3/5y ) = s β 2
[(t(5x + 3y) Γ· 25)] = s β 2
t(5x + 3y) = 25 (s β 2)
5x + 3y = [(25(s β 2))Γ· t]
5x = [(25(s β 2))Γ· t] β 3y
Divide both sides by 5
x = [25(s β 2) β 3ty)]Γ· 5t
t/5(x + 3/5y ) = s β 2
[(t(5x + 3y) Γ· 25)] = s β 2
t(5x + 3y) = 25 (s β 2)
5x + 3y = [(25(s β 2))Γ· t]
5x = [(25(s β 2))Γ· t] β 3y
Divide both sides by 5
x = [25(s β 2) β 3ty)]Γ· 5t
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