Question on: JAMB Mathematics - 1993
Make x the subject of the relation (\frac{1 + ax}{1 - ax}) = (\frac{p}{q})
A
\(\frac{p + q}{a(p - q)}\)
B
\(\frac{p - q}{a(p + q)}\)
C
\(\frac{p - q}{apq}\)
D
\(\frac{pq}{a(p - q)}\)
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Correct Option: B
(\frac{1 + ax}{1 - ax}) = (\frac{p}{q}) by cross multiplication,
q(1 + ax) = p(1 - ax)
q + qax = p - pax
qax + pax = p - q
∴ x = (\frac{p - q}{a(p + q)})
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