Question on: WAEC Mathematics - 1997
O is the centre of the circle PQRS. PR and QS intersect at T POR is a diameter, ∠PQT = 42o and ∠QTR = 64o; Find ∠QRT
A
68o
B
64o
C
42o
D
32o
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Correct Option: A
TQR = 90 - 42 = 48o
QRT = 180 - (64 - 48)
= 180 - 112
= 68o
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