Question on: JAMB Mathematics - 2015
One bag contain 3 blue and 5 red balls, another bag contain 2 blue and 4 red balls respectively. One ball is drawn for each bag. What is the probability both balls are blue
A
\( \frac{2}{15} \)
B
\( \frac{3}{24} \)
C
\( \frac{3}{21} \)
D
\( \frac{3}{28} \)
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Correct Option: D
One bag with 3 blue and 5 red
Pr (H) = 3/8Pr (r) 5/8
Another bag with 2 blue and 4 red (note one ball is drawn from each bag)
i.e. prob.=8 − 1 = 7
prob. (2 ball both are blue=pr (1st blue and 2nd blue)
prob. 2 balls both blue = 3/8 × 2/7
= ( \frac{3}{28} )
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