Question on: JAMB Chemistry - 2006
One mole of a hydrocarbon contains 36g of carbon and its vapour density is 20. The structure of the hydrocarbon is
A
CH3C ≡ CH
B
CH3CH = CH2
C
CH3CH2C ≡ CH
D
CH3CH2 CH3
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Correct Option: A
2VD = Rmm VD = Vapour density; Rmm - Relative
2 * 20 = 40 Molecular mass
Mole of carbon = 36/12 = 3
Mole of H2 = 40 - 36 = 4
The compound contains 3 mole of carbon and 4 hydrogen
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