p begin vmatrix x amp 3 amp 0 2 amp y amp 3 4 a... - JAMB Mathematics 1992 Question
p = \(\begin{vmatrix} x & 3 & 0 \ 2 & y & 3\ 4 & 2 & 4 \end{vmatrix}\)
Q = \(\begin{vmatrix} x & 2 & z \ 3 & y & 2\ 0 & 3 & z \end{vmatrix}\) Where pT is the transpose P calculate /pT/ when x = 0, y = 1 and z = 2
Q = \(\begin{vmatrix} x & 2 & z \ 3 & y & 2\ 0 & 3 & z \end{vmatrix}\) Where pT is the transpose P calculate /pT/ when x = 0, y = 1 and z = 2
A
48
B
24
C
-24
D
-48
correct option: b
p = \(\begin{vmatrix} 0 & 3 & 0 \ 2 & 1 & 3\ 4 & 2 & 2 \end{vmatrix}\)
PT = \(\begin{vmatrix}0 & 2 & 4 \ 2 & 1 & 3\ 0 & 3 & 2 \end{vmatrix}\)
/pT/ = \(\begin{vmatrix}0 & 2 & 4 \ 3 & 1 & 3\ 0 & 3 & 2 \end{vmatrix}\)
= 0[2 - 6] - 2[6 - 0] + 4[9 - 0]
= 0 - 12 + 36 = 24
PT = \(\begin{vmatrix}0 & 2 & 4 \ 2 & 1 & 3\ 0 & 3 & 2 \end{vmatrix}\)
/pT/ = \(\begin{vmatrix}0 & 2 & 4 \ 3 & 1 & 3\ 0 & 3 & 2 \end{vmatrix}\)
= 0[2 - 6] - 2[6 - 0] + 4[9 - 0]
= 0 - 12 + 36 = 24
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