Question on: JAMB Mathematics - 2013
P varies jointly as m and u, and varies inversely as q. Given that p = 4, m = 3 and u = 2 and q = 1, find the value of p when m = 6, u = 4 and q =(\frac{8}{5})
P (\propto) mu, p (\propto \frac{1}{q})
p = muk ................ (1)
p = (\frac{1}{q}k).... (2)
Combining (1) and (2), we get
P = (\frac{mu}{q}k)
4 = (\frac{m \times u}{1}k)
giving k = (\frac{4}{6} = \frac{2}{3})
So, P = (\frac{mu}{q} \times \frac{2}{3} = \frac{2mu}{3q})
Hence, P = (\frac{2 \times 6 \times 4}{3 \times \frac{8}{5}})
P = (\frac{2 \times 6 \times 4 \times 5}{3 \times 8})
p = 10
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