Question on: WAEC Mathematics - 2002
Points X, Y and Z are located in the same horizontal plane such that Y is 12 km north of X and Z is on a bearing of 270° from X. If |XZ| = 6km, calculate, correct to one decimal place, lYZl
A
18km
B
13.4km
C
13km
D
10.4km
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Correct Option: B
ZY\(^2\) = 12\(^2\) + 6\(^2\)
ZY\(^2\) = 144 + 36 = 180
ZY = \(\sqrt{180}\)
= \(13.416\)
= 13.4 km
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