Question on: WAEC Mathematics - 2007
PQR is an equilateral triangle with sides 2\(\sqrt{3cm}\). calculate its height
A
1.7cm
B
3.0cm
C
3.2cm
D
3.9cm
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Correct Option: B
By Pythagoras theorem
h2 = (2\(\sqrt{3})^2 - (\sqrt{3})^2\)
= 22(\(\sqrt{3})^2 - 3\)
4(3) - 3 = 112 - 3
h2 = 9
h = \(\sqrt{9}\)
= 3cm
h2 = (2\(\sqrt{3})^2 - (\sqrt{3})^2\)
= 22(\(\sqrt{3})^2 - 3\)
4(3) - 3 = 112 - 3
h2 = 9
h = \(\sqrt{9}\)
= 3cm
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