Question on: WAEC Mathematics - 2009
PQRS is a trapezuim. QR//PS, /PQ/ = 5cm, /OR/ = 6cm, /PS/ = 10cm and angle QPS = 42o. Calculate the perpendicular distance between the parallel sides
A
3.35cm
B
3.73cm
C
4.50cm
D
4.62cm
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Correct Option: A
h = ?
\(\frac{h}{5cm}\) = sin 45o
h = 5cm x 0.6691 = 3.35cm
\(\frac{h}{5cm}\) = sin 45o
h = 5cm x 0.6691 = 3.35cm
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