RS aq HF aq RF s HS aq H -65 7 kj mol -1 From t... - JAMB Chemistry 1999 Question
RS(aq) + HF(aq) → RF(s) + HS(aq)
ΔH = -65.7 kj mol(-1).
From the equation above, it can be deduced that
ΔH = -65.7 kj mol(-1).
From the equation above, it can be deduced that
A
the heat content of the reactants is lower than that of the products
B
the heat content of the reactants is higher than that of the products
C
the reaction is slow
D
a large amount of heat is absorbed
correct option: b
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