simple harmonic oscillator has a period of 0 02... - WAEC Physics 2010 Question
simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed in ms-1 at the centre of the oscillation
A
125\(\pi\)
B
25.00\(\pi\)
C
100.00 \(\pi\)
D
400.00\(\pi\)
correct option: b
V = WX = \(\frac{2\pi \times 0.25}{0.02} = 25\pi\)
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