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Question on: JAMB Mathematics - 2017

Simplify 4\(\sqrt{27}\) + 5\(\sqrt{12}\) βˆ’ 3\(\sqrt{75}\)
A
7
B
βˆ’ 7
C
βˆ’ 7\(\sqrt{3}\)
D
7\(\sqrt{3}\)
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Correct Option: D
4\(\sqrt{27}\) + 5\(\sqrt{12}\) βˆ’ 3\(\sqrt{75}\)

= 4\(\sqrt{3}\) Γ— 9 + 5\(\sqrt{3}\) Γ— 4 βˆ’ 3\(\sqrt{3}\) Γ— 25

= 4 Γ— 3\(\sqrt{3}\) + 5 Γ— 2\(\sqrt{3}\) βˆ’ 3 Γ— 5\(\sqrt{3}\)

= 12\(\sqrt{3}\) + 10\(\sqrt{3}\) βˆ’ 15\(\sqrt{3}\)

= (12 + 10 βˆ’ 15)\(\sqrt{3}\)

= 7\(\sqrt{3}\)

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