Question on: JAMB Mathematics - 2017
Simplify 4\(\sqrt{27}\) + 5\(\sqrt{12}\) β 3\(\sqrt{75}\)
A
7
B
β 7
C
β 7\(\sqrt{3}\)
D
7\(\sqrt{3}\)
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Correct Option: D
4\(\sqrt{27}\) + 5\(\sqrt{12}\) β 3\(\sqrt{75}\)
= 4\(\sqrt{3}\) Γ 9 + 5\(\sqrt{3}\) Γ 4 β 3\(\sqrt{3}\) Γ 25
= 4 Γ 3\(\sqrt{3}\) + 5 Γ 2\(\sqrt{3}\) β 3 Γ 5\(\sqrt{3}\)
= 12\(\sqrt{3}\) + 10\(\sqrt{3}\) β 15\(\sqrt{3}\)
= (12 + 10 β 15)\(\sqrt{3}\)
= 7\(\sqrt{3}\)
= 4\(\sqrt{3}\) Γ 9 + 5\(\sqrt{3}\) Γ 4 β 3\(\sqrt{3}\) Γ 25
= 4 Γ 3\(\sqrt{3}\) + 5 Γ 2\(\sqrt{3}\) β 3 Γ 5\(\sqrt{3}\)
= 12\(\sqrt{3}\) + 10\(\sqrt{3}\) β 15\(\sqrt{3}\)
= (12 + 10 β 15)\(\sqrt{3}\)
= 7\(\sqrt{3}\)
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