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Simplify \( \frac{1}{(x + 1)} + \frac{1}{(x βˆ’ 1)} \)
Correct Option: B
[1 Γ· (x+1)] + [1 Γ· (x βˆ’ 1)]

= ((x βˆ’ 1) + [(x + 1)) Γ· (x+1)(x βˆ’ 1)]

Using the L.C.M.

= (x βˆ’ 1 + x + 1) Γ· (x + 1)(x βˆ’ 1)

= (x + 2 βˆ’ 1 + 1) Γ· (x + 1)(x βˆ’ 1)

= 2x Γ· (x + 1)(x βˆ’ 1) =2x Γ· (x + 1)(x βˆ’ 1)