Simplify frac 1 x-3 - frac 3 x-1 x 2 - 9 - WAEC Mathematics 2000 Question
Simplify \(\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}\)
A
\(\frac{x-1}{x-3}\)
B
\(\frac{-2}{x+3}\)
C
\(\frac{x-1}{x+3}\)
D
\(\frac{4x}{x^2-9}\)
correct option: b
\(\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}\
\frac{1}{x-3}-\frac{3(x-1)}{(x-3)(x+3)}\
\frac{x+3-3x+3}{(x-3)(x+3)};\frac{-2x+6}{(x-3)(x+3)}\
\frac{-2(x-3)}{(x-3)(x+3)}=\frac{-2}{x+3}\)
\frac{1}{x-3}-\frac{3(x-1)}{(x-3)(x+3)}\
\frac{x+3-3x+3}{(x-3)(x+3)};\frac{-2x+6}{(x-3)(x+3)}\
\frac{-2(x-3)}{(x-3)(x+3)}=\frac{-2}{x+3}\)
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