Question on: WAEC Mathematics - 2003
Simplify \(\frac{4}{a-3}-\frac{1}{a+3}\)
A
\(\frac{3a+11}{(a-3)(a-2)}\)
B
\(\frac{3a+11}{(a+3)(a-2)}\)
C
\(\frac{3a+11}{(a+3)(a+2)}\)
D
\(\frac{3a+11}{(a-3)(a+2)}\)
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Correct Option: D
\(\frac{4}{a-3}-\frac{1}{a+3}\
= \frac{4(a+2)-1(a-3)}{(a-3)(a+2)}\
=\frac{3a+11}{(a-3)(a+2)}
\)
= \frac{4(a+2)-1(a-3)}{(a-3)(a+2)}\
=\frac{3a+11}{(a-3)(a+2)}
\)
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