Question on: JAMB Mathematics - 1990
Simplify \(\sqrt{160r^2}\) + \(\sqrt{71r^4}\) + \(\sqrt{100r^2}\)
A
9r2
B
12\(\sqrt{3r}\)
C
13r
D
\(\sqrt{13r}\)
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Correct Option: C
\(\sqrt{160r^2 + 71r^4 + 100r^8}\)
Simplifying from the innermost radical and progressing outwards we have the given expression
\(\sqrt{160r^2 + 71r^4 + 100r^8}\) = \(\sqrt{160r^2 + 81r^4}\)
\(\sqrt{160r^2 + 9r^2}\) = \(\sqrt{169r^2}\)
= 13r
Simplifying from the innermost radical and progressing outwards we have the given expression
\(\sqrt{160r^2 + 71r^4 + 100r^8}\) = \(\sqrt{160r^2 + 81r^4}\)
\(\sqrt{160r^2 + 9r^2}\) = \(\sqrt{169r^2}\)
= 13r
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