Question on: SS1 Mathematics - Number Forms (Indices And Logarithm)
Solve \(4^{x} = \frac{1}{64}\)
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\(4^{x} = \frac{1}{64}\ \rightarrow \ 4^{x} = \ \frac{1}{2^{6}}\ \rightarrow \ 4^{x} = \ 2^{- 6}\ \rightarrow \ 2^{2x} = \ 2^{- 6},\ comparing\ powers,\ thus,\ 2x = \ - 6\ \rightarrow x = \frac{- 6}{2} = \ - 3\)
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