Question on: JAMB Mathematics - 2022
Solve for k in the equation \(\frac{1}{8}^{k+2}\) = 1
A
2
B
-4
C
-2
D
4
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Correct Option: C
To solve the equation \\(\\frac{1}{8}^{k+2}\\) = 1, we need to find the value of *k*.
Here's how:
1. **Recognize that any non-zero number raised to the power of 0 equals 1.** Therefore, for \\(\\frac{1}{8}^{k+2}\\) to equal 1, the exponent (k+2) must be equal to 0.
2. **Set the exponent equal to 0:** k + 2 = 0
3. **Solve for k:** Subtract 2 from both sides of the equation: k = -2
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