Question on: JAMB Mathematics - 1994
Solve for x and y \(\begin{pmatrix} 1 & 1 \ 3 & y \end{pmatrix}\)\(\begin{pmatrix} x \ 1 \end{pmatrix}\) = \(\begin{pmatrix} 4 \ 1\end{pmatrix}\)
A
x = 3, y = 8
B
x = 3, y = -8
C
x = -8, y = 3
D
x = 8, y = -3
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Correct Option: B
\(\begin{pmatrix} 1 & 1 \ 3 & y \end{pmatrix}\)\(\begin{pmatrix} x \ 1 \end{pmatrix}\) = \(\begin{pmatrix} 4 \ 1\end{pmatrix}\) = x + 1 = 4
x = 4 - 1
= 3
3x + y =1
3(3) = y = 1
= 9 + y = 1
y = 1 - 9
= -8
x = 4 - 1
= 3
3x + y =1
3(3) = y = 1
= 9 + y = 1
y = 1 - 9
= -8
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