Solve for x in frac 4x - 6 3 leq frac 3 2x 2 - JAMB Mathematics 2019 Question
Solve for x in \(\frac{4x - 6}{3} \leq \frac{3 + 2x}{2}\)
A
\(x \leq 1\frac{1}{2}\)
B
\(x \leq \frac{21}{2}\)
C
\(x \geq \frac{21}{2}\)
D
\(x \geq 1\frac{1}{2}\)
correct option: b
\(\frac{4x - 6}{3} \leq \frac{3 + 2x}{2}\)
2(4x - 6) \(\leq\) 3(3 + 2x)
8x - 12 \(\leq\) 9 + 6x
8x - 6x \(\leq\) 9 + 12
2x \(\leq\) 21
\(x \leq \frac{21}{2}\)
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