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Solve for x in the equation 4 x 1 8 x - SS2 Mathematics Logarithm Question

Solve for $x$ in the equation $4^{x + 1} = 8^{x}$

$4^{x + 1} = 8^{x}$

$2^{2 x + 2} = 2^{3 x}$

$2 x + 2 = 3 x$

$2 = 3 x - 2 x$

$2 = x$

$x = 2$

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