Question on: WAEC Mathematics - 2009
solve (\frac{2x + 1}{6} - \frac{3x - 1}{4}) = 0
A
1
B
\(\frac{1}{5}\)
C
-\(\frac{1}{5}\)
D
-1
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Correct Option: A
(\frac{2x + 1}{6} - \frac{3x - 1}{4}) = 0
(\frac{4(2n + 1) - 6(3x - 1)}{24}) = 0
-10x + 10 = 0
-10x = -10
x = (\frac{-10}{-10})
x = 1
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