solve frac 2x 1 6 - frac 3x - 1 4 0 - WAEC Mathematics 2009 Question
solve \(\frac{2x + 1}{6} - \frac{3x - 1}{4}\) = 0
A
1
B
\(\frac{1}{5}\)
C
-\(\frac{1}{5}\)
D
-1
correct option: a
\(\frac{2x + 1}{6} - \frac{3x - 1}{4}\) = 0
\(\frac{4(2n + 1) - 6(3x - 1)}{24}\) = 0
-10x + 10 = 0
-10x = -10
x = \(\frac{-10}{-10}\)
x = 1
\(\frac{4(2n + 1) - 6(3x - 1)}{24}\) = 0
-10x + 10 = 0
-10x = -10
x = \(\frac{-10}{-10}\)
x = 1
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